V4RB - Valentina.EscapeString

[Christian - ChrisKatDev.com]

Hi,

I think only first parameter with 4.7
I have same problem with V4md

Happy new year
Christian

Envoyé de mon iPhone

Le 1 janv. 2011 à 00:10, Steve Albin <steve at steve-albin.com> a écrit :

> I recently upgraded from V4RB 4.3 to V4RB 4.7.  My previously  
> working projects all used the following code:
>    str1 = Valentina.EscapeString(inputStr,True)
>
> After upgrading, I get compile errors saying "This method requires  
> fewer parameters than were passed".  I created a test project  
> eliminating the second parameter and EscapeString seems to work fine  
> without it.
>
> The wiki documentation still says this method takes 2 parameters.   
> Can I assume this is an error in the documentation?  I don't  
> understand why this would change.
>
> Steve
>
>
> --
> Steve Albin, Montclair, NJ
> http://www.steve-albin.com
> http://www.jazzdiscography.com
>
> _______________________________________________
> Valentina mailing list
> Valentina at lists.macserve.net
> http://lists.macserve.net/mailman/listinfo/valentina