V4RB - Valentina.EscapeString

[Steve Albin]

I recently upgraded from V4RB 4.3 to V4RB 4.7.  My previously working projects all used the following code:
	str1 = Valentina.EscapeString(inputStr,True)

After upgrading, I get compile errors saying "This method requires fewer parameters than were passed".  I created a test project eliminating the second parameter and EscapeString seems to work fine without it.  

The wiki documentation still says this method takes 2 parameters.  Can I assume this is an error in the documentation?  I don't understand why this would change.

Steve


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Steve Albin, Montclair, NJ
http://www.steve-albin.com
http://www.jazzdiscography.com