bitSet and Arrayset + problem with "bitset=new bitset (count, arrayset)"

[Olivier]

> But they will do the same conversion, so you will no win speed.
>
ok
> In the worse case you can add own wrapper-functions to remove 
> duplicated
> code. Right ?
right


BitSet and ArraySet are SO fast in theory the one as the other one? 
Right?

What makes that the one or the other one will be faster will depend 
only the memory used? That's right?

If we use a bitSet with small one selection of returned records or an 
arrayset with a big selection of returned records, the code will be 
badly optimized and will maybe be slower, that's right?

olivier