How does works "group by" correct
SoftIl
softil at onlinehome.de
Mon Aug 16 12:38:52 CDT 2004
Hallo Halldor,
thanks for your answer.
Now I understand where my mistake was.
I didn't know that I can use goup by only with an aggregate function.
Now it is clear, why it could not work.
Thanks
Carsten
----- Original Message -----
From: "Halldor Gislason" <halldorg at vortex.is>
To: "Valentina Developers" <valentina at lists.macserve.net>
Sent: Thursday, August 12, 2004 11:49 PM
Subject: Re: How does works "group by" correct
> "select *" returns all the fields so a group by does not really have a
> purpose there.
>
> the purpose of the group by is to group the results of some aggregate
> function by some fields so a group by without such a function has
> little point
>
> you may instead be looking for the UNIQUE statement that will not
> return records with duplicate values of of the field values you specify
> as unique - I do not know how well Valentina supports UNIQUE
>
> to group by more than one field simply do:
>
> select a,b, count(*) from c group by a,b
>
> or
>
> select a,b, sum(c) from d group by a,b
>
> h
>
>
>
> On Aug 12, 2004, at 9:34 PM, SoftIl wrote:
>
> > Hi all,
> > I've got some problems with "group by":
> >
> > 1)
> > If I try this:
> > select * from myTable group by date
> > the "group by" statement hasn't an effect.
> >
> > If I write this
> > select *,count(any column) from myTable group by date
> > it works correct.
> >
> > Why is it so? In no documentation I could find this, that I have to use
> > "count()" if I'd like to use "group by".
> >
> > 2)
> > How can I use "group by" for more than one column?
> > This statement works not correct. I get all records return:
> > select *,count(any column) from myTable group by date,ohrnummer
> >
> > Thanks for your help.
> > Carsten
> >
> >
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> > Valentina at lists.macserve.net
> > http://lists.macserve.net/mailman/listinfo/valentina
> >
>
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