Record ID Problem
Michael Krugman
admin at ktinet.net
Mon Nov 24 17:49:06 CST 2003
Hi Rusian and List:
I'm trying to convert my RB app, using the RB Database to Valentina. I
am able to create and open the database. I use a listbox to display
the contents. With the RB database, the first field was the ID (Record
ID). I need to be able to display the record id with Valentina, just
as I did with RB. Below is the code that I used in RB, except for the
GetString change at the end of each line. ID represents the Record ID
in the RB database. Can someone take a look at this and give me an
idea of how to display Valentina's record ID? The rest of the code
depends on the record id. In my listbox, it should display as the
first column. Any help is appreciated.
Mike
////////////////////////////////////
// Add a Specific Record to the List //
///////////////////////////////////
dim curs as Databasecursor
// Get the specific record into a DatabaseCursor
curs = myDataBase.SQLSelect("SELECT * FROM Clients WHERE ID =" +
str(ID))
// Since there is only one record we don't need to use a loop
// Add row to the listbox
Customers.addrow curs.Field("ID).GetString
Customers.cell(customers.listCount-1, 1) =
curs.Field("Last").GetString
Customers.cell(customers.listCount-1, 2) =
curs.Field("First").GetString
Customers.cell(customers.listCount-1, 3) =
curs.Field("Initial").GetString
Customers.cell(customers.listCount-1, 4) =
curs.Field("Social").GetString
Customers.cell(customers.listCount-1, 5) =
curs.Field("Address").GetString
Customers.cell(customers.listCount-1, 6) =
curs.Field("City").GetString
Customers.cell(customers.listCount-1, 7) =
curs.Field("State").GetString
Customers.cell(customers.listCount-1, 8) =
curs.Field("ZipCode").getString
Customers.cell(customers.listCount-1, 9) =
curs.Field("HomePhone").GetString
Customers.cell(customers.listCount-1, 10) =
curs.Field("WorkPhone").GetString
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